5y^2=28y

Solution for 5y^2=28y equation:

5y^2=28y

We move all terms to the left:

5y^2-(28y)=0

a = 5; b = -28; c = 0;
Δ = b2-4ac
Δ = -282-4·5·0
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-28}{2*5}=\frac{0}{10}
=0
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+28}{2*5}=\frac{56}{10}
=5+3/5
$